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5u^2+60u+100=0
a = 5; b = 60; c = +100;
Δ = b2-4ac
Δ = 602-4·5·100
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40}{2*5}=\frac{-100}{10} =-10 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40}{2*5}=\frac{-20}{10} =-2 $
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